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31 lines
1.0 KiB
Markdown
31 lines
1.0 KiB
Markdown
# $(<node-name>).all(branchIndex?: number, runIndex?: number)
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This gives access to all the items of the current or parent nodes. If you don't supply any parameters, it returns all the items of the current node.
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## Getting items
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```typescript
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// Returns all the items of the given node and current run
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const allItems = $("<node-name>").all();
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// Returns all items the node "IF" outputs (index: 0 which is Output "true" of its most recent run)
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const allItems = $("IF").all();
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// Returns all items the node "IF" outputs (index: 0 which is Output "true" of the same run as current node)
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const allItems = $("IF").all(0, $runIndex);
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// Returns all items the node "IF" outputs (index: 1 which is Output "false" of run 0 which is the first run)
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const allItems = $("IF").all(1, 0);
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```
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## Accessing item data
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Get all items output by a previous node, and log out the data they contain:
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```typescript
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previousNodeData = $("<node-name>").all();
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for(let i=0; i<previousNodeData.length; i++) {
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console.log(previousNodeData[i].json);
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}
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```
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